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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

The degree of dissociation is 0.4 at 420 K and 1.0 atm for the...

The degree of dissociation is 0.4 at 420 K and 1.0 atm for the gaseous reaction

PCl5(g)⟶PCl3(g)+Cl2(g)PC{l}_{5}\left(g\right) ⟶ PC{l}_{3}\left(g\right) + C{l}_{2} ( g ). Assuming ideal behavior of all gases, calculate the density of equilibrium mixture of equilibrium mixture at 420 K and 1.0 atm. (P = 31, Cl = 35.5)

Options

  1. A4.30
  2. B3.54
  3. C2.64
  4. D1.56

Correct answer

A. 4.30

Step-by-step solution

{PCl5(g)⇌PCl3(g)+Cl2(g)t=0a00teq0.6a0.4a0.4a\begin{cases} & {PCl}_{5} \left(\text{g}\right) & ⇌ & {PCl}_{3} \left(\text{g}\right) & + & {Cl}_{2} \left(\text{g}\right) \\ \text{t} = 0 & \text{a} & & 0 & & 0 \\ {t}_{eq} & \text{0.6a} & & \text{0.4a} & & \text{0.4a}\end{cases}

nTotal=1.4a{n}_{Total} = 1.4a

∴Mav=208a1.4a=148.57∴Pmix=PMavRT=1×148.570.0821×420=4.30\begin{array}{ll}∴ {M}_{av} = \dfrac{208a}{1.4a} \\ = 148.57 \\ ∴ {P}_{mix} = \dfrac{{P}_{{M}_{av}}}{RT} \\ = \dfrac{1 \times 148.57}{0.0821 \times 420} = 4.30\end{array}
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