NTA Abhyas JEE Main2020ChemistryChemical EquilibriumPractice
The degree of dissociation is 0.4 at 420 K and 1.0 atm for the gaseous reaction P C l 5 g ⟶ P C l 3 g + C l 2 ( g ) . Assuming ideal behavior of all gases, calculate the density of equilibrium mixture of equilibrium mixture at 420 K and 1.0 atm. (P = 31, Cl = 35.5)
Options
- A4.30
- B3.54
- C2.64
- D1.56
Correct answer
A. 4.30
Step-by-step solution
PCl 5 g ⇌ PCl 3 g + Cl 2 g t = 0 a 0 0 t eq 0.6a 0.4a 0.4a n Total = 1.4 a ∴     M a v = 208   a 1.4   a                           = 148.57 ∴     P m i x = P M a v R T                             = 1 × 148.57 0.0821 × 420 = 4.30