20% of N 2 O 4 molecules are dissociated in a sample of gas at 27 ° C and 760 torr. Mixture has the density at equilibrium equal to

Step-by-step solution

The reaction is N 2 O 4 ( g ) ⇌ 2 N O 2 ( g ) n = 2 and α = 20 100 = 0.2 D = 4.6, initial vapour density d = vapour density at equilibrium α = D - d ( n - 1 ) d 0.2 = 46 - d ( 2 - 1 ) d d = 38.3 Molar mass equilibrium = 2 × 38.3 = 76.6 PM   =   dRT Here, d = density of gas mixture d(mix)   =   PM RT   =  1   ×   76 .6 0 .0821   ×   300   =   3 .12   g/L