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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

20% of N _ 2 O _ 4 molecules are dissociated in a sample of gas at...

20% of N2O4{N}_{2}{O}_{4} molecules are dissociated in a sample of gas at 27°27 ° C and 760 torr. Mixture has the density at equilibrium equal to

Options

  1. A1.48 g/L
  2. B1.84 g/L
  3. C2.25 g/L
  4. D3.12 g/L

Correct answer

D. 3.12 g/L

Step-by-step solution

The reaction is
N2O4(g)⇌2NO2(g){N}_{2}{O}_{4} ( g ) ⇌ 2N{O}_{2} ( g )
n = 2 and α=20100=0.2\alpha = \dfrac{20}{100} = 0.2
D = 4.6, initial vapour density
d = vapour density at equilibrium
α=D−d(n−1)d\alpha = \dfrac{D - d}{( n - 1 ) d}
0.2=46−d(2−1)d0.2 = \dfrac{46 - d}{( 2 - 1 ) d}
d = 38.3
Molar mass equilibrium =2×38.3=76.6= 2 \times 38.3 = 76.6
PM=dRT\text{PM}\text{=}\text{dRT}
Here, d = density of gas mixture
d(mix)=PMRT=1\times76.60.0821\times300\text{d(mix)}\text{=}\dfrac{\text{PM}}{\text{RT}} \text{=}\dfrac{\text{1}\text{\times}\text{76}\text{.6}}{\text{0}\text{.0821}\text{\times}\text{300}}
=3.12g/L\text{=}\text{3}\text{.12}\text{g/L}
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