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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

NTA Abhyas 2020 · Chemistry · Chemical Equilibrium

The equilibrium, N H _ 4 HS ( s ) ⇌ N H _ 3 ( g ) + H _ 2 S ( g ) ,...

The equilibrium, NH4HS(s)⇌NH3(g)+H2S(g)N{H}_{4}HS ( s ) ⇌ N{H}_{3} ( g ) + {H}_{2}S ( g ) , is followed to set-up at 127°C127 ° C in a closed vessel. The total pressure at equilibrium was 20 atm. The KC{K}_{C} for the reaction is

Options

  1. A0.092{\textM^{2}
  2. B0.085{\textM^{2}
  3. C3.045{\textM^{2}
  4. DNone of these

Correct answer

A. 0.092{\textM^{2}

Step-by-step solution

pNH3=pH2S=202=10atmpN{H}_{3} = p{H}_{2}S = \dfrac{20}{2} = 10\text{atm}
KP=pNH3×pH2S{K}_{P} = pN{H}_{3} \times p{H}_{2}S
=100atm2= 100\text{at}m^{2}
KP=KC(RT)\Deltan{K}_{P} = {K}_{C} ( RT{)}^{\Deltan}
100=KC(0.0821×400)2100 = {K}_{C} ( 0.0821 \times 400{)}^{2}
KC=0.092M2{K}_{C} = 0.092M^{2}.
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