NTA Abhyas JEE Main2020ChemistryHydrocarbonsPractice
An alkane of molecular weight 86 g/mol on monochlorination gives two products. The alkane is
Options
- A2-Methylbutane
- Bn-butane
- C2, 2-Dimethyl propane
- D2, 3-Dimethyl butane
Correct answer
D. 2, 3-Dimethyl butane
Step-by-step solution
C n H 2 n + 2 = 86 12 n + 2 n + 2 = 86 14 n = 84 n = 6 molecular formula = C 6 H 14 for two monochloro products alkane must have 2-type H