NTA Abhyas JEE Main2020ChemistryHydrocarbonsPractice
In compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular weight of compound is 108. Molecular formula of compound is
Options
- AC 2 H 6 N 2
- BC 3 H 4 N
- CC 6 H 8 N 2
- DC 9 H 12 N 3
Correct answer
C. C 6 H 8 N 2
Step-by-step solution
Percentage R.N.A. Simplest ratio C 9 9 12 = 3 4 3 H 1 1 1 = 1 4 N 35 3.5 14 = 1 4 1 Empirical formula = C 3 H 4 N C 3 H 4 N n = 108 , 12 × 3 + 4 × 1 + 14 n = 108 54 n = 108 n = 108 54 = 2 So molecular formula = 2 × C 3 H 4 N = C 6 H 8 N 2