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[ P ] → Br 2 C 2 H 4 Br 2 → NaNH 2 Q → 20 % H 2 SO 4 R → ZnHg/HCl S The species P, Q, R and S respectively are

Options

  1. Aethene, ethyne, ethanal, ethane
  2. Bethane, ethyne, ethanal, ethene
  3. Cethene, ethyne, ethanal, ethanol
  4. Dethyne, ethane, ethene, ethanal

Correct answer

A. ethene, ethyne, ethanal, ethane

Step-by-step solution

[ P ] → Br 2 C 2 H 4 Br 2 → NaNH 2 Q → 20 % H 2 SO 4 R → ZnHg/HCl S As 'P' undergoes addition reaction with 1 mole of B r 2 it means there is only 1 double bond So 'P' is C 2 H 4 C H 2 = C H 2 and the reaction is as follows Here P, Q, R and S are ethene, ethyne, ethanal and ethane respectively

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