NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
Calculate dissociation constant for an acid HA having [ H + ] equals to 0 .1 M (Given: degree of dissociation of HA is 1% )
Options
- A1 0 -8
- B1 0 -6
- C1 0 -3
- D1 0 -7
Correct answer
C. 1 0 -3
Step-by-step solution
k a = α 2 C 1 - α , α is very small ; ∴ 1 - α ≈ 1 Cα = 0 .1 k a = (Cα)α = 0.01 × 0.1 = 10 − 3