NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
What is the OH − concentration of a 0 .04 M solution of CH 3 COONa? [K a of CH 3 COONa = 2 × 10 − 5 , log 2 = 0 .30, log 5 = 0 .69, 10 0 .7 ≅ 5]
Options
- A5 × 10 - 6
- B6 × 10 - 6
- C2 × 10 - 9
- D3 × 10 - 9
Correct answer
A. 5 × 10 - 6
Step-by-step solution
pK a = − log K a = − log (2 × 10 − 5 ) = 5 - l o g 2 = 5 - 0.3 = 4.7 pH = 1 2 pK w + pK a + log C p H = 1 2 [ 14 + 4.7 + log 0.04 ] p H = 8.63 pOH   =   14 − 8 .63   ≅   5 .3 O H - = 5 × 10 - 6