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When 10 mL of 0 .1 M acetic acid (pK a = 5) is titrated against 10 mL of 0 .1 M ammonia solution (pK b = 5 ) , the equivalent point will occur at pH :

Options

  1. A5
  2. B6
  3. C7
  4. D9

Correct answer

C. 7

Step-by-step solution

CH 3 COOH (aq) + NH 3 (aq) → CH 3 COONH 4 (aq) 1 m mol 1 m mol 1 m mol CH 3 COONH 4 = 1 mM 20 mL = 0 .05 M Salt of weak Acid + weak base. pH = 1 2 p K w + p K a - p K b = 1 2 1 4 + 5 - 5 = 7

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