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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Ionic Equilibrium

NTA Abhyas 2020 · Chemistry · Ionic Equilibrium

If the pK_ a of a weak acid HA is 4.80 and the pK_ b of a weak base...

If the {\text{pK}_{a} of a weak acid HA\text{HA} is 4.80\text{4}\text{.80} and the {\text{pK}_{b} of a weak base BOH\text{BOH} is 4.78.\text{4}\text{.78}\text{.} Then, the pH\text{pH} of an aqueous solution of the corresponding salt, BA\text{BA} will be

Options

  1. A8.23
  2. B9.41
  3. C7.01
  4. D5.91

Correct answer

C. 7.01

Step-by-step solution

BOH+HA→B++A−+H2O\text{BOH} + \text{HA} \to B^{+} + A^{−} + {H}_{2} \text{O}
\text{pH} = \dfrac{1}{2} {\text{pK}_{w} + \dfrac{1}{2} {\text{pK}_{a} - \dfrac{1}{2} {\text{pK}_{b}
=12(14+4.80−4.78)=7.01= \dfrac{1}{2} \left(14 + 4.80 - 4.78\right) = 7.01
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