NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
If the pK a of a weak acid HA is 4 .80 and the pK b of a weak base BOH is 4 .78 . Then, the pH of an aqueous solution of the corresponding salt, BA will be
Options
- A8.23
- B9.41
- C7.01
- D5.91
Correct answer
C. 7.01
Step-by-step solution
BOH + HA → B + + A − + H 2 O pH = 1 2  pK w + 1 2   pK a − 1 2 pK b =   1 2 14 + 4.80 − 4.78 = 7.01