NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
The ionization constant of a weak monobasic acid is 25 × 1 0 – 6 while the equivalent conductance of its 0.01 M solution is 19.6 S c m 2 e q – 1 . The equivalent conductance of the electrolyte at infinite dilution ( i n S c m 2 e q – 1 ) will be
Options
- A250
- B196
- C392
- D384
Correct answer
C. 392
Step-by-step solution
K a = Cα 2 25 × 1 0 – 6 = 0.01 α 2 α = 5 × 1 0 – 2 α = Λ e q Λ e q o 5 × 1 0 – 2 = 19.6 Λ e q o Λ e q o = 19.6 5 × 1 0 – 2 = 392