NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
Using the Gibbs energy change, Δ G ° = + 63.3 kJ , for the following reaction, A g 2 C O 3 → 2 A g + ( a q ) + C O 3 2 - ( a q ) the K s p of A g 2 C O 3 ( s ) in water at 25 o C is ( R = 8.314 J K - 1 m o l - 1 ) Given: 10 0.91 ≅ 8
Options
- A7.9 × 1 0 - 2
- B8.0 × 1 0 - 12
- C2.9 × 1 0 - 3
- D3.2 × 1 0 - 26
Correct answer
B. 8.0 × 1 0 - 12
Step-by-step solution
ΔG o = − 2.303   RT   log   K sp 63.3 × 1000 = - 2.303 × 8.314 × 298 log K s p log K s p = - 11.09 K s p = 1 0 - 11.09 = 8 × 1 0 - 12