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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Ionic Equilibrium

NTA Abhyas 2020 · Chemistry · Ionic Equilibrium

The solubility of a sparingly soluble salt A (OH)^ 2 (mol. wt....

The solubility of a sparingly soluble salt AA\left(OH\right)^{2}(mol.wt.192.3)is(mol. wt. 192.3) is19.23 g / litreatat300K.The. ThepHofitssaturatedsolutionassuming80of its saturated solution assuming 80% ionisation at300K is :

Options

  1. A1.09701.0970
  2. B12.903012.9030
  3. C13.204113.2041
  4. D12.000012.0000

Correct answer

C. 13.204113.2041

Step-by-step solution

S=19.23192.3mol/litre=0.1 M\text{S} = \dfrac{\text{19.23}}{\text{192.3}} \text{mol/litre} = \text{0.1 M}
{A(OH)2⇌A2++2OH−2S\begin{cases}\text{A} {\left(\text{OH}\right)}_{2} & ⇌ & A^{2 +} & + & 2 {OH}^{-} \\ & & & & 2 \text{S}\end{cases}
∴[OH−]=0.1×2×80100=0.16∴ \left[{OH}^{-}\right] = \dfrac{\text{0.1} \times 2 \times 8 0}{1 0 0} = \text{0.16}
∴pOH=0.7958∴ \text{pOH} = \text{0.7958}
∴pH=13.2041∴ \text{pH} = \text{13.2041}
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