NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
The solubility of a sparingly soluble salt A OH 2 (mol. wt. 192.3) is 19 .23 g / litre at 300 K . The pH of its saturated solution assuming 80% ionisation at 300 K is :
Options
- A1.0970
- B12.9030
- C13.2041
- D12.0000
Correct answer
C. 13.2041
Step-by-step solution
S = 19.23 192.3 mol/litre = 0.1 M A OH 2 ⇌ A 2 + + 2 OH - 2 S ∴ OH - = 0.1 × 2 × 8 0 1 0 0 = 0.16 ∴ pOH = 0.7958 ∴ pH = 13.2041