NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
The degree of dissociation of acetic acid in a 0 .1 M solution is 1.0 × 1 0 – 2 . The p K a of acetic acid value.
Options
- A3
- B4
- C5
- D6
Correct answer
C. 5
Step-by-step solution
K a = C α 2 1 - α = 0.1 × 1 0 - 2 2 1 - 0.01 = 1.01 × 1 0 - 5 p K a = - log 1 × 1 0 - 5 = 5