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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Ionic Equilibrium

NTA Abhyas 2020 · Chemistry · Ionic Equilibrium

The degree of dissociation of acetic acid in a 0.1M solution is 1.0...

The degree of dissociation of acetic acid in a 0.1M\text{0}\text{.1}\text{M} solution is 1.0×10–21.0 \times 1{0}^{– 2}. The pKap{K}_{a} of acetic acid value.

Options

  1. A3
  2. B4
  3. C5
  4. D6

Correct answer

C. 5

Step-by-step solution

Ka=Cα21−α=0.1×(10−2)2(1−0.01)=1.01×10−5{K}_{a} = \dfrac{C{\alpha}^{2}}{1 - \alpha} = \dfrac{0.1 \times {\left(1{0}^{- 2}\right)}^{2}}{\left(1 - 0.01\right)} = 1.01 \times 1{0}^{- 5}
pKa=−log⁡(1×10−5)=5p{K}_{a} = - \log \left(1 \times 1{0}^{- 5}\right) = 5
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