NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
In 1 L saturated solution of AgCl K sp AgCl = 1.6 × 1 0 - 10 , 0.1 mol of CuCl K sp CuCl = 1.0 × 1 0 - 6 is added. The resultant concentration of A g + in the solution is 1.6 × 10 - x . The value of " x " is
Correct answer
7
Step-by-step solution
Let the solubility of A g C l is x mol litr e - 1 AgCl ⇌ A g + x + C l - x And that of C u C l is y mol litr e - 1 CuCl ⇌ C u + y + C l - y K sp of AgCl = A g + C l - 1 1.6 × 1 0 - 10 = x x + y ...(i) Similarly K sp of CuCl = C u + C l - 1.6 × 1 0 - 6 = y x + y ...(ii) On solving (i) and (ii) A g + = 1.6 × 1 0 - 7 x = 7