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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Ionic Equilibrium

NTA Abhyas 2020 · Chemistry · Ionic Equilibrium

Calculate the pH of solution when 100mL, 0.1MC H _ 3 COOH and...

Calculate the pHpH of solution when 100mL,0.1MCH3COOH100mL, 0.1MC{H}_{3}COOH and 100mL,0.1MHCOOH100mL, 0.1MHCOOH are mixed together. (Given: Ka(CH3COOH)=2×10–5,Ka(HCOOH)=6×10–5{K}_{a}\left(C{H}_{3}COOH\right) = 2 \times {10}^{– 5}, {K}_{a}\left(HCOOH\right) = 6 \times 1{0}^{– 5} )

Correct answer

2.7

Step-by-step solution

As the volume is doubled, concentration would be half. The total [H+]\left[{\text{H}}^{\text{+}}\right] is obtained by addition of [H+]\left[{\text{H}}^{\text{+}}\right]from both acids.
[H+]=(Ka1C1+Ka2C2)[ {H}^{+} ] = \sqrt{\left({K}_{a1}{C}_{1} + {K}_{a2}{C}_{2}\right)}
=(2×10−5×0.12+6×10−5×0.12)= \sqrt{\left(2 \times 1{0}^{- 5} \times \dfrac{0.1}{2} + 6 \times 1{0}^{- 5} \times \dfrac{0.1}{2}\right)}
=2×10−3= 2 \times 1{0}^{- 3}
pH=2.7pH = 2.7
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