Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Redox Reactions

NTA Abhyas 2020 · Chemistry · Redox Reactions

2.56 × 10 ^ - 3 equivalent of KOH is required to neutralise...

2.56×10−32.56 \times {10}^{- 3} equivalent of KOH\text{KOH} is required to neutralise \text{0}\text{.12544}\text{g}{H}_{2} {\text{XO}_{4}. The atomic mass of X\text{X} (in g/mol\text{g/mol} ) is:
[Given: {H}_{2} {\text{XO}_{4} is a dibasic acid]

Options

  1. A1616
  2. B88
  3. C77
  4. D3232

Correct answer

D. 3232

Step-by-step solution

Let the atomic weight of X=y\text{X}\text{=}\text{y}
No. of equivalents of KOH\text{KOH} = No. of equivalents of {H}_{2} {\text{XO}_{4}
i.e. 0.1254466+y2=0.12544\dfrac{\text{0}\text{.12544}}{\dfrac{\text{66}\text{+}\text{y}}{2}} \text{=}\text{0}\text{.12544}
∴y=32∴ \text{y}\text{=}\text{32}
Practice Redox Reactions on Quantrex Academy →

More from Redox Reactions

500 mL of 0.2 M MnO _4^- solution in basic medium when mixed with 500 mL of 1.5 M KI… JEE Main 2026Given below are two statements: Statement I: Sodium dichromate and potassium dichromate… JEE Main 2026In order to oxidise a mixture of 1 mole each of FeC_2O_4 , Fe_2(C_2O_4)_3 , FeSO_4 and… JEE Main 2026500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2 M KMnO_ 4 solution in basic… JEE Main 2026One mole of Cl_ 2 (~g) was passed into 2 L of cold 2 M KOH solution. After the reaction… JEE Main 2026X and Y are the number of electrons involved, respectively during the oxidation of I^… JEE Main 2026200 cc of x × 10^ -3 M potassium dichromate is required to oxidise 750 cc of 0.6 M Mohr's… JEE Main 2026Identify the correct statements : A. Hydrated salts can be used as primary standard. B.… JEE Main 2026 Full Redox Reactions list All NTA Abhyas JEE Main PYQs