What will be the value of x, y and z in the following equation? H _...

(i) The half reaction for oxidation is,
${H}_{2}{C}_{2}{O}_{4} \to C{O}_{2}$
Balancing carbon atoms on both sides, ${H}_{2}{C}_{2}{O}_{4} \to 2C{O}_{2}$
Balancing hydrogen atoms on both sides, ${H}_{2}{C}_{2}{O}_{4} \to 2C{O}_{2} + 2H^{+}$
Balancing the charge on both sides,
${H}_{2}{C}_{2}{O}_{4} \to 2C{O}_{2} + 2H^{+} + 2e^{-}$...(i)
(ii) The half reaction for reduction is‐ ${H}_{2} {O}_{2} \to {H}_{2} \text{O}$
Balancing oxygen atoms on both sides, ${H}_{2}{O}_{2} \to 2{H}_{2}O$
Balancing hydrogen atoms, ${H}_{2}{O}_{2} + 2H^{+} \to 2{H}_{2}O$
Balancing the charge,
${H}_{2}{O}_{2} + 2H^{+} + 2e^{-} \to 2{H}_{2}O$...(ii)
Now, adding both equations, ${H}_{2}{C}_{2}{O}_{4} + {H}_{2}{O}_{2} \to 2C{O}_{2} + 2{H}_{2}O$
This is balanced equation so x, y, z are 1,2,2 respectively.