A metal oxide has the formula Z _ 2 O _ 3 . It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

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Correct answer: D. 55.8

Z _ 2 O _ 3 + 3 H _ 2 → 2Z + 3 H _ 2 O Valency of metal in Z _ 2 O _ 3 = 3 0.1596 g of Z _ 2 O _ 3 react with 6 mg of H _ 2 So 1 g of H _ 2 react with = (0.1596)/(0.006) = 26.6 g of Z _ 2 O _ 3 So Eq. wt. of Z _ 2 O _ 3 = 26.6 Now, Eq. wt. of Z + Eq. wt. of O = Eq. wt. of Z + 8 = 26.6 So Eq. wt. of Z = 26.6 - 8 = 18.6 So At. wt. of Z = 18.6 × 3 = 55.8

A metal oxide has the formula Z _ 2 O _ 3 . It can be reduced by...

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