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NTA Abhyas JEE Main2020ChemistryRedox ReactionsPractice

A metal oxide has the formula Z 2 O 3 . It can be reduced by hydrogen to give free metal and water. 0.1596 g of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of the metal is

Options

  1. A27.9
  2. B159.6
  3. C79.8
  4. D55.8

Correct answer

D. 55.8

Step-by-step solution

Z 2 O 3 + 3 H 2 → 2 Z + 3 H 2 O Valency of metal in Z 2 O 3 = 3 0 .1596 g of Z 2 O 3 react with 6 mg of H 2 So 1 g of H 2 react with = 0.1596 0.006 = 26.6 g of Z 2 O 3 So Eq. wt. of Z 2 O 3 = 26.6 Now, Eq. wt. of Z + Eq. wt. of O = Eq. wt. of Z + 8 = 26.6 So Eq. wt. of Z = 26.6 - 8 = 18.6 So At. wt. of Z = 18.6 × 3 = 55.8

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