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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Redox Reactions

NTA Abhyas 2020 · Chemistry · Redox Reactions

1.5 gm sample of bleaching powder was suspended in water. It was...

1.5 gm sample of bleaching powder was suspended in water. It was treated with CH3COOHC{H}_{3}COOH followed by the addition of excess of KI. The liberated iodine required 150 mL of M10\dfrac{M}{10} hypo solution for complete titration. The percentage of available chlorine in the sample is

Correct answer

35.5

Step-by-step solution

2KI+Cl2→2KCl+I22KI + C{l}_{2} \to 2KCl + {I}_{2}

I2+2S2O32−→2I−+S4O62−{I}_{2} + 2{S}_{2}{O}_{3}^{2 -} \to 2{I}^{-} + {S}_{4}{O}_{6}^{2 -}

Mol of available Cl2≡C{l}_{2} ≡ mole of iodine

=1×150×10−310×2= \dfrac{1 \times 150 \times 1{0}^{- 3}}{10 \times 2}

Amount of available Cl2C{l}_{2}

=150×10−320×71g= \dfrac{150 \times 1{0}^{- 3}}{20} \times 71g

% of available Cl2C{l}_{2}

=150×10−3×71×10020×1.5=35.5= \dfrac{150 \times 1{0}^{- 3} \times 71 \times 100}{20 \times 1.5} = 35.5
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