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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Redox Reactions

NTA Abhyas 2020 · Chemistry · Redox Reactions

0.2 g sample of benzoic acid, C _ 6 H _ 5 COOH is titrated with...

0.2 g sample of benzoic acid, C6H5COOH{C}_{6}{H}_{5}COOH is titrated with 0.12 M Ba ( OH ){\left(\text{ OH }\right)}_{2}solution.Whatvolumeofsolution. What volume ofBa ( OH{)}_{2}solutionisrequiredtoreachtheequivalencepoint?<br/>Molarmassofbenzoicacidis122gsolution is required to reach the equivalence point? <br/>Molar mass of benzoic acid is 122 gmol^{- 1}.

Options

  1. A6.83 mL
  2. B13.6 mL
  3. C17.6 mL
  4. D35.2 mL

Correct answer

A. 6.83 mL

Step-by-step solution

Number of moles of benzoic acid =0.2122=1.64×10−3= \dfrac{0.2}{122} = 1.64 \times 1{0}^{- 3}
Neutralization takes place as
2C6H5COOH+Ba(OH)2→(C6H5COO)2Ba+2H2O2{C}_{6}{H}_{5}COOH + Ba ( OH{)}_{2} \to ( {C}_{6}{H}_{5}COO{)}_{2}Ba + 2{H}_{2}O
Number of moles of Ba(OH)2Ba ( OH{)}_{2} required =12×1.64×10−3= \dfrac{1}{2} \times 1.64 \times 1{0}^{- 3}
MV1000=12×1.64×10−3\dfrac{MV}{1000} = \dfrac{1}{2} \times 1.64 \times 1{0}^{- 3}
0.12×V1000=12×1.64×10−3\dfrac{0.12 \times V}{1000} = \dfrac{1}{2} \times 1.64 \times 1{0}^{- 3}
V = 6.83 mL
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