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NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Chemistry
Chapter: Redox Reactions

NTA Abhyas 2020 · Chemistry · Redox Reactions

Find out the % of oxalate ion in given sample of oxalate salt of...

Find out the

%

of oxalate ion in given sample of oxalate salt of which

0 . 3g

is present in

100mL

of solution required

90mL

of

N / 20KMn{O}_{4}

for complete oxidation.

Correct answer

66.00

Step-by-step solution

The redox changes are

{\text{Mn}}^{+ 7} + 5{\text{e}}^{-} \to {\text{Mn}}^{2 +}

{\left({\text{C}}^{3 +}\right)}_{2} \to 2{\text{C}}^{4 +} + 2{\text{e}}^{-}

∵ \text{meq. of oxalate ion=meq}{\text{. of KMnO}}_{4}

\left(w / E\right) \times 1000 = 90 \times \left(1 / 20\right)

<br />Or \left(\dfrac{\text{w}}{88 / 2}\right) \times 1000 = \dfrac{9}{2} \left(∵ {\text{E}}_{{\text{C}}_{2} {\text{O}}_{4}^{- 2}} = \dfrac{88}{2}\right)

or

{\text{w}}_{{\text{C}}_{2} {\text{O}}_{4}^{- 2}} = 0.198\text{g}

∴

% of oxalate in sample

= ( 0.198 \times 100 ) / 0.3 = 66%

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