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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Redox Reactions

NTA Abhyas 2020 · Chemistry · Redox Reactions

A 100ml solution of 0.1N - HCl was titrated with 0.2N - NaOH...

A 100ml100ml solution of 0.1N−HCl0.1N - HCl was titrated with 0.2N−NaOH0.2N - NaOH solution. The titration was discontinued after adding 30ml30ml of NaOHNaOH solution. The remaining titration was completed by adding 0.25N−KOH0.25N - KOH solution. The volume of KOHKOH required for completing the titration is

Options

  1. A16ml16ml
  2. B32ml32ml
  3. C35ml35ml
  4. D70ml70ml

Correct answer

A. 16ml16ml

Step-by-step solution

In the neutralization of acid and base N×VN \times V of both must be equivalent

N×VofHCl=0.1×100=10N \times VofHCl = 0.1 \times 100 = 10

N×VofNaOH=0.2×30=6N \times VofNaOH = 0.2 \times 30 = 6

N1V1(ml)=N×VNaOH(ml)+N×V(ml)KOH{N}_{1}{V}_{1}\left(ml\right) = \mathop{N \times V}_{NaOH}\left(ml\right) + \mathop{N \times V\left(ml\right)}_{KOH}

0.1×100=0.2×30+0.25×V0.1 \times 100 = 0.2 \times 30 + 0.25 \times V

10=6+0.25V10 = 6 + 0.25V

V=40025V=16mlV = \dfrac{400}{25}V = 16ml
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