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Find the values of x , y , z in the given balanced equation H 2 S O 4 + x H I → H 2 S + y I 2 + z H 2 O ,

Options

  1. Ax = 3 , y = 5 , z = 2
  2. Bx = 4 , y = 8 , z = 5
  3. Cx = 8 , y = 4 , z = 4
  4. Dx = 5 , y = 3 , z = 4

Correct answer

C. x = 8 , y = 4 , z = 4

Step-by-step solution

Sulphur gains 8 electron in reduction and iodide ion loses 1 electron in oxidation. Thus values of x , y , z are 8, 4, 4 respectively hence the reaction is H 2 S O 4 + 8 H I → H 2 S + 4 I 2 + 4 H 2 O

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