Find the sum of the coefficients “a, b, candd” , in the given...

$I{{O}_{3}}^{–} + a{I}^{–} + b{H}^{+} \to c{H}_{2}O + d{I}_{2}$

Step 1: ${I}^{– 1} \to {I}_{2}\left(oxidation\right)<br /><br />$I{{O}_{3}}^{–} \to {I}_{2}\left(reduction\right)$<br /><br />Step 2:$2I{{O}_{3}}^{–} + 12{H}^{+} \to {I}_{2} + 6{H}_{2}O$<br /><br />Step 3:$2I{{O}_{3}}^{–} + 12{H}^{+} + 10e \to {I}_{2} + 6{H}_{2}O$<br /><br />$2{{I}^{–}}_{} \to {I}_{2} + 2e$<br /><br />Step 4:$2I{{O}_{3}}^{–} + 12{H}^{+} + 10{e}^{–} \to {I}_{2} + 6{H}_{2}O$<br /><br />\left[2{I}^{–} \to {I}_{2} + 2e\right]5$

Step 5: $2I{{O}_{3}}^{–} + 10{I}^{–} + 12{H}^{+} \to 6{I}_{2} + 6{H}_{2}O$

$I{{O}_{3}}^{–} + 5{I}^{–} + 6{H}^{+} \to 3{I}_{2} + 3{H}_{2}O$

On comparing, $a = 5, b = 6, c = 3, d = 3$