NTA Abhyas JEE Main2020ChemistrySolutionsPractice
Benzene and napthalene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and naphthalene at 300 K are 50.71 mm of Hg and 32.06 mm of Hg respectively. What will be the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of naphthalene?
Options
- A0.0675
- B0.675
- C0.35
- D0.5
Correct answer
B. 0.675
Step-by-step solution
P ° A X A P ° B X B = X A ' X B ' 50 .71 80 78 32 .06 100 128 = X A ' 1 - X A ' X A ' = 0 .675