The solubility of N 2 in water at 300 K and 500 torr partial pressure 0 .01 g L − 1 . The solubility (in g L − 1 ) at 750 torr partial pressure is:

Step-by-step solution

P 2   =   K H X 2 where P 2 → partial presence of gas X 2 → mole fraction of gas in solution K H   = Henry's law constant So, P ∝ solubility p 1 p 2 = s 1 s 2 ⇒ 500 0 .01 = 750 x ∴ x = 0 .015 g/L