2.0 molal aqueous solution of an electrolyte X 2 Y 3 is 75 % ionised. The boiling point of the solution a 1 a t m is K b ( H 2 O ) = 0.52 K k g m o l - 1

Step-by-step solution

X 2 Y 3 ( a q ) → 2 X 3 + ( a q ) + 3 Y 2 - a q n = 5 Δ T b = i K b . m = ( 1 + 4 α ) K b m = ( 1 + 4 × 0.75 ) × 0.52 × 2 = 4.16 ; T b = 373 + 4.16 = 374.76