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The vapour pressure of pure liquid A is 10 torr and at the same temperature when 9 g of B solid dissolved in 20 g of A, its Vapour pressure is reduced to 5 torr . If the molecular mass of A is 200 amu, then the molecular mass of B is

Options

  1. A100 amu
  2. B90 amu
  3. C75 amu
  4. D120 amu

Correct answer

B. 90 amu

Step-by-step solution

P 0 - P s P s = n N 10 - 5 5 = 9 × 200 M × 20 M   =   90   amu

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