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NTA Abhyas JEE Main2020ChemistrySolutionsPractice

K 2 H g I 4 is 55% ionized in aqueous solution. The value of Van't Hoff factor is

Options

  1. A2.1
  2. B4.3
  3. C1.9
  4. D3.7

Correct answer

A. 2.1

Step-by-step solution

K 2 H g I 4 → 2 K + + H g I 4 2 - ⇒ i   =   1   +   n − 1 α ⇒ i   =   1   +   0 .55 3-1   ( ∵ n = 3 ) ∴   i = 2.1

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