NTA Abhyas JEE Main2020ChemistrySolutionsPractice
The concentration in g/L of a solution of cane sugar (Molecular weight = 342) which is isotonic with a solution containing 6 g of urea (Molecular weight = 60) per litre is
Options
- A3.42
- B34.2
- C5.7
- D19
Correct answer
B. 34.2
Step-by-step solution
The two solution should have same molar concentration for being isotonic. Molar concentration of cabe sugar = Molar concentration of urea = 6 6 0 = 0.1 mol/L concentration of cane sugar in g/L = molar concentration  ×  molecular weight =   0 .1   ×   342   =   34 .2