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NTA Abhyas JEE Main2020ChemistrySolutionsPractice

A 5.25 % solution of a substance is isotonic with a 1.5 % solution of urea (molar mass = 60 g mol – 1 ) in the same solvent. If the densities of both the solutions are assumed to be equal to 1.0 g cm – 3 , molar mass of the substance will be

Options

  1. A105.0  g   mol – 1
  2. B210.0  g   mol – 1
  3. C90.0  g   mol – 1
  4. D15.0  g   mol – 1

Correct answer

B. 210.0  g   mol – 1

Step-by-step solution

π s o l u t i o n = π u r e a 5.25 M = 1.5 60 M = 5.25 × 60 1.5 = 210.0  g   mol – 1

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