The vapour pressure of pure water at 26 o C is 25 .5 torr . . The vapour pressure of a solution which contains 20 .0 glucose, (C 6 H 12 O 6 ) , in 100 g water (in torr) is?

Step-by-step solution

By raoult's law P A ο - P A P A ο = n B n A + n B Or P A ο - P A P A = n B n A P A := the partial vapour pressure of the component display style i in the gaseous mixture (above the solution), P A ο = the vapour pressure of the pure component n B : moles of solute n A : moles of solvent P A ο - P A P A = n B n A 25.5 - P A P A = 20 180 100 18 25.5 - P A P A = 20 × 18 100 × 180 = 0.02 25.5 − P A = 0.02   P A 1.02   P A = 25.5 P A = 25.0