NTA Abhyas JEE Main2020ChemistrySolutionsPractice
A solution containing 10 g of a non-volatile, higher nonelectrolyte and 400 g of water boils at 100 .256 o C at 1 atm . The molecular weight of the solute (in g/mol) is Given: ( K b for water 0.512 C ο / m )
Correct answer
50
Step-by-step solution
Δ T b = i × K b × m 0.256 = 1 × 0.512 × 10.0 M 0.4 M = 0.512 × 10.0 0.4 × 0.256 M = 50   g/mol