NTA Abhyas JEE Main2020ChemistrySolutionsPractice
Mixture of voltaic component A and B has total vapure pressure (in torr) P = 254 - 119 X A . Where X A is mole fraction of A in the mixture. Hence, P A 0 & P B 0 (in torr) are:
Options
- A254 , 199
- B119 , 254
- C135 , 254
- D119 , 373
Correct answer
C. 135 , 254
Step-by-step solution
For X A = 0 ,  P B 0 = 254 For X A = 1 ,  P A 0 = 254 – 119   = 135