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NTA Abhyas JEE Main2020ChemistrySolutionsPractice

If latent heat of fusion of ice is 80 cals per g at 0 o C , calculate molal depression constant for water.

Options

  1. A18.63
  2. B186.3
  3. C1.863
  4. D0.1863

Correct answer

C. 1.863

Step-by-step solution

K f = R T f 2 1000 × l V Here R = 2 c a l s , T f = 0 + 273 = 273 , l f = 80 c a l s K f = 2 × 273 × 273 1000 × 80 = 1.863

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