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The freezing point of equimolal aqueous solution will be highest for

Options

  1. AC 6 H 5 N + H 3 C l - (aniline hydrochloride)
  2. BC a ( N O 3 ) 2
  3. CL a ( N O 3 ) 3
  4. DC 6 H 12 O 6 (Glucose)

Correct answer

D. C 6 H 12 O 6 (Glucose)

Step-by-step solution

Δ T f ∝ m × i m = morality, i = Vant Hoff factor Except glucose, all other a electrolytes are undergoing dissociation so ( i > 1 ) . Glucose is non electrolyte, i = 1 . so it has least value of Δ T f hence its freezing point is maximum.

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