NTA Abhyas JEE Main2020ChemistrySolutionsPractice
At 48 ° C the vapour pressure of pure C S 2 is 850 torr. A solution of 2.0 g of sulphur in 100 g of C S 2 has a vapour pressure 844.9 torr. Determine the atomicity of sulphur molecule :
Options
- A1
- B2
- C4
- D8
Correct answer
D. 8
Step-by-step solution
Δ P = 5.1 torr ; x is atomicity of sulphur. Δ P P A ∘ = 5.1 850 = X B = 2 3 2 x 2 3 2 x + 1 0 0 7 6 5.1 850 ≅ 2 3 2 x × 7 6 1 0 0 x = 2 × 7 6 3 2 × 1 0 0 × 8 5 0 5.1 = 7.92 ≈ 8