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The weight of glucose dissolved in 100 gm of water produce same lowering of vapor pressure as 1 gm urea dissolved in 50 g m of water at same temperature is

Correct answer

6

Step-by-step solution

since same lowering in vapour pressure. X solute of urea = X solute of glucose 1 60 1 60 + 50 18 = w 180 w 180 + 100 18 ⇒ 1 60 50 18 = w 180 100 18 (For dilute solution) ⇒ w = 6 of glucose

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