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NTA Abhyas JEE Main2020ChemistrySolutionsPractice

How much amount of NaCl should be added to 600 g of water ( ρ = 1.00 g / m L ) to decrease the freezing point of water to – 0.2 o C ? (The freezing point depression constant for water = 2 K kg mo l - 1 )

Options

  1. A2.14 g
  2. B0.88 g
  3. C1.96 g
  4. D1.76 g

Correct answer

D. 1.76 g

Step-by-step solution

Δ T f = 0.2 Δ T f = i K f m i = 2 for NaCl 0.2 = 2 × 2 × m m = w 58.5 × 1000 600 0.2 = 2 × 2 × w 58.5 × 1000 600 w = 0.2 × 58.5 × 600 4 × 600 = 1.2 × 58.5 40 = 1.76 g

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