NTA Abhyas JEE Main2020ChemistrySolutionsPractice
In a galvanic cell, after running the cell for sometime, the concentration of the electrolyte is automatically raised to 3 m HCl. Molar conductivity of the 3 m HCl is about 240 S c m 2 m o l - 1 and limiting molar conductivity of HCl is about 420 S c m 2 m o l - 1 . If K b of water is 0.52 K kg m o l - 1 , calculate the boiling point of the electrolyte at the end of the experiment.
Options
- A375.6 K
- B376.3 K
- C378.1 K
- D380.3 K
Correct answer
A. 375.6 K
Step-by-step solution
α = Molar conductivity Limiting molar conductivity = 240 420 = 12 21 α = i - 1 n - 1 = i - 1 2 - 1 = 12 21 i = 12 21 + 1 = 33 21 Δ T b = i K b m = 33 21 × 0.52 × 3 = 2.45 K T b = T b o + Δ T b = 373.15 + 2.45 = 375.6 K