When a gas is bubbled through water at 298 K, a very dilute solution of gas is obtained. Henry's law constant for the gas is 100 kbar. If gas exerts a pressure of 1 bar, the number of moles of gas dissolved in 1 litre of water is x × 10 − 5 . Find the value of x here? Report your answer upto two decimal places.

Step-by-step solution

p = K H × x x = p K H = 1 100 × 1 0 3 = 1 × 1 0 - 5 Mole of fraction = Mole of gas Total moles Moles of H 2 O   =   1000 18   =   55 .55   ∴ 1   L   =   1000   g   ×   10 − 5 Mole fraction = x x + 55.55 55.55 > > > x So 1 0 - 5 = x 55.55 or x = 55.55 × 1 0 - 5