30 mL of 0 . 1 M K I ( a q ) and 10 mL of 0 . 2 M A g N O 3 are mixed. The solution is then filtered out. Assuming no change in total volume, depression in freezing point of the resulting solution will be : (Given : K f for H 2 O = 1 . 86 K

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30 mL of 0 . 1 M K I ( a q ) and 10 mL of 0 . 2 M A g N O 3 are mixed. The solution is then filtered out. Assuming no change in total volume, depression in freezing point of the resulting solution will be : (Given : K f for H 2 O = 1 . 86 K kg mol - 1 , assume molarity = molality)

Quantrex Academy · Accepted Answer

Correct answer: 0.28

KI (aq) + AgNO 3 (aq) ⟶ KNO 3( (aq) + AgI (s) millimoles 3 0 × 0 . 1 1 0 × 0 . 2 3 2 0 0 mm left 1 0 2 2 ∴ [KI] in solution = 1 4 0 and [KNO 3 ] = 2 4 0 & (Assuming molarity = molality for dilute soluation) ∴ Δ T f = Δ T f ( b y K I ) + Δ T f ( b y K N O 3 ) = molality × 1.86 × i KI + molality × 1.86 × i KNO 3 = ( 1 40 × 1.86 × 2 ) + ( 2 40 × 1.86 × 2 ) = 0 . 0 9 3 + 0 . 1 8 6 = 0 . 2 7 9 = 0.28 ° C

30 mL of 0 . 1 M K I ( a q ) and 10 mL of 0 . 2 M A g N O 3 are mixed. The solution is then filtered out. Assuming no change in total volume, depression in freezing point of the resulting solution will be : (Given : K f for H 2 O = 1 . 86 K kg mol - 1 , assume molarity = molality)

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