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NTA Abhyas JEE Main2020ChemistrySolutionsPractice

A solution containing 1.8 g of a compound (empirical formula CH 2 O ) in 40 g of water is observed to freeze at - 0 .465 ∘ C . The molecular formula of the compound is- ( K f of water = 1 .86 kg K mol - 1 )

Options

  1. AC 2 H 4 O 2
  2. BC 3 H 6 O 3
  3. CC 5 H 10 O 5
  4. DC 6 H 12 O 6

Correct answer

D. C 6 H 12 O 6

Step-by-step solution

M 2 = K f × w 2 × 1000 △ T f × w 1 or M 2 = 1 .86 × 1 .8 × 1000 0 .465 × 40 = 180 n = 180 emp . formula mass = 180 30 = 6 Molecular formula of the compound is C 6 H 12 O 6 .

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