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The mass (in grams) of glucose that should be dissolved in 100 g of water in order to produce same lowering of vapour pressure as is produced by dissolving 1 g of urea (molecular mass = 60) in 50 g of water is

Correct answer

6.00

Step-by-step solution

Δ P P 0 = X B ≈ n B n A = w B × m A m B × w A w B × m A m B × w A g l u c o s e = w B × m A m B × w A u r e a w B × 18 180 × 100 = 1 × 18 60 × 50 w B = 6 g.

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