Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185000 in 450 mL of water at 37 o C.

Step-by-step solution

Mass of polymer (W B ) = 1.0 g Molar mass of polymer (M B ) = 185000 g mol -1 Volume of solution (V) = 450 mL = 0.450 L Temperature (T) = 37 + 273 = 310 K Solution constant (R) = 8.314 x 10 3 Pa L K -1 mol -1 Osmotic pressure π = CRT = W B × R × T M B × V π = 1.0 g × 8.314 × 10 3 Pa L K - 1 mol - 1 × 310 K 185000 g mol - 1 × 0.450 L = 30.95 Pa