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NTA Abhyas JEE Main2020ChemistrySolutionsPractice

If a 0.004 M solution of N a 2 S O 4 is isotonic with a 0.010 M solution of glucose at same temperature. Then what is the apparent degree of disociation of N a 2 S O 4 is

Options

  1. A25%
  2. B50%
  3. C75%
  4. D85%

Correct answer

C. 75%

Step-by-step solution

N a 2 S O 4 ( 0.004 - x ) ⇌ 2 N a + 2 x + S O 4 2 - x Since both the solution are isotonic 0.004 + 2 x = 0.01 x = 0.003 H N O 2 Percent dissociation. = 3 × 1 0 - 3 0.004 × 100 = 75 % .

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