NTA Abhyas JEE Main2020ChemistrySolutionsPractice
For a liquid the vapour pressure is given by log 10 P = - 400 T + 10 Vapour pressure of the liquid is 10 x mm Hg at 400 K . The value of x will be?
Correct answer
9
Step-by-step solution
log 10 P = - 400 T + 10 = - 400 400 + 10 = 9 P = 10 9 mm Hg x = 9 .