NTA Abhyas JEE Main2020ChemistrySolutionsPractice
5 g sulphur is present in 100 g of C S 2 . Δ T b of solution 0.954 and K b is 4.88. The molecular formula of sulphur is
Options
- AS 2
- BS 4
- CS 3
- DS 8
Correct answer
D. S 8
Step-by-step solution
ΔT b = K b × m m = Δ T b K b or W 2 × 1000 M 2 × W 1 = Δ T b K b or 5 × 1000 M 2 × 100 = 0.954 4.88 M 2 = 256 Atomic weight of sulphur = 32 Number of sulphur atom = M o l e c u l a r weight A t o m i c weight = 256 32 = 8 Hence Molecular formula = S 8 .