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If Z - 2 = 2 Z - 1 , then the value of R e Z Z 2 is (where Z is a complex number and Re( Z ) represents the real part of Z )

Correct answer

0.75

Step-by-step solution

Let, Z = x + i y ⇒ x - 2 + i y = 2 x - 1 + i y ⇒ x - 2 2 + y 2 = 4 x - 1 2 + y 2 ⇒ 3 x 2 + y 2 - 4 x = 0 ⇒ x x 2 + y 2 = 3 4 ⇒ R e Z Z 2 = 0 . 7 5

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